-[3z-(6z+3)]=3+(2z+1)

Solution for -[3z-(6z+3)]=3+(2z+1) equation:

Simplifying
-1[3z + -1(6z + 3)] = 3 + (2z + 1)

Reorder the terms:
-1[3z + -1(3 + 6z)] = 3 + (2z + 1)
-1[3z + (3 * -1 + 6z * -1)] = 3 + (2z + 1)
-1[3z + (-3 + -6z)] = 3 + (2z + 1)

Reorder the terms:
-1[-3 + 3z + -6z] = 3 + (2z + 1)

Combine like terms: 3z + -6z = -3z
-1[-3 + -3z] = 3 + (2z + 1)
[-3 * -1 + -3z * -1] = 3 + (2z + 1)
[3 + 3z] = 3 + (2z + 1)

Reorder the terms:
3 + 3z = 3 + (1 + 2z)

Remove parenthesis around (1 + 2z)
3 + 3z = 3 + 1 + 2z

Combine like terms: 3 + 1 = 4
3 + 3z = 4 + 2z

Solving
3 + 3z = 4 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
3 + 3z + -2z = 4 + 2z + -2z

Combine like terms: 3z + -2z = 1z
3 + 1z = 4 + 2z + -2z

Combine like terms: 2z + -2z = 0
3 + 1z = 4 + 0
3 + 1z = 4

Add '-3' to each side of the equation.
3 + -3 + 1z = 4 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 4 + -3
1z = 4 + -3

Combine like terms: 4 + -3 = 1
1z = 1

Divide each side by '1'.
z = 1

Simplifying
z = 1